基于独立分量分析的实正交空时分组码盲识别

doi:10.3969/j.issn.1000-436x.2012.11.001

摘要/Abstract

摘要：

提出一种基于独立分量分析的正交空时分组码(OSTBC)盲识别方法。首先给出了接收信号模型，利用独立分量分析得到含有编码矩阵的虚拟信道矩阵，然后利用编码矩阵特性，证明得到正交空时分组码的虚拟信道矩阵的相关矩阵为对角矩阵；最后提出用于正交空时分组码识别的2个特征参数：稀疏度和方差。仿真结果表明，所提出方法能够较好地识别正交空时分组码。

关键词: MIMO系统, 正交空时分组码, 盲识别, 虚拟信道矩阵

Abstract:

A method for blind recognition of orthogonal space-time block coding (OSTBC) based on independent component analysis (ICA) was proposed.Firstly,the model of received signal was given.And then independent component analysis technology was used to separate the virtual channel matrix which contains coding matrix information.Using the characteristics of coding matrix,it was proved that the correlation matrix of the virtual channel matrix in OSTBC communication systems was diagonal matrix.Finally,two characteristic parameters were proposed: sparsity and variance,which could recognize OSTBC.Simulation results demonstrated that the proposed method is able to identify OSTBC while achieves good performance.

Key words: MIMO systems, orthogonal space-time block coding, blind recognition, virtual channel matrix

赵知劲,陈林,王海泉,沈雷. 基于独立分量分析的实正交空时分组码盲识别[J]. 通信学报, 2012, 33(11): 1-7.

Zhi-jin ZHAO,Lin CHEN,Hai-quan WANG,Lei SHEN. Blind recognition of real orthogonal STBC based on independent component analysis[J]. Journal on Communications, 2012, 33(11): 1-7.

图/表 10

表1

无噪声时矩阵 A ^ "

n_R	正交空时分组码 $\hat{A}$	非正交空时分组码 $\hat{A}$
n_R=1	$[\begin{matrix} 30.5691 & - 0.5067 & 0.2263 & - 1.4978 \\ - 0.5067 & 29.9989 & - 0.3723 & 0.6550 \\ 0.2263 & - 0.3723 & 29.8941 & 0.7057 \\ - 1.4978 & 0.6550 & 0.7057 & 29.5379 \end{matrix}]$	$[\begin{matrix} 28.7895 & 1.3533 & - 7.3138 & - 3.1636 \\ 1.3533 & 31.0566 & - 2.0280 & - 1.3136 \\ - 7.3138 & - 2.0280 & 30.4094 & - 2.2663 \\ - 3.1636 & - 1.3136 & - 2.2663 & 29.5151 \end{matrix}]$
n_R=2	$[\begin{matrix} 30.8392 & 0.3310 & - 0.6614 & 0.7853 \\ 0.3310 & 30.4584 & 0.2703 & - 0.7554 \\ - 0.6614 & 0.2703 & 30.3270 & - 0.0888 \\ 0.7853 & - 0.7554 & - 0.0888 & 29.5754 \end{matrix}]$	$[\begin{matrix} 30.7348 & 1.9415 & - 1.4580 & - 0.8610 \\ 1.9415 & 30.1225 & - 1.7593 & 2.2053 \\ - 1.4580 & - 1.7593 & 29.2791 & 0.6580 \\ - 0.8610 & 2.2053 & 0.6580 & 29.8187 \end{matrix}]$

表1

表2

S NR=5 dB时矩阵 A ^ "

n_R	正交空时分组码 $\hat{A}$	非正交空时分组码 $\hat{A}$
n_R=1	$[\begin{matrix} 40.5572 & 0.3766 & - 0.0147 & - 0.4304 \\ 0.3766 & 39.9744 & 1.6558 & - 0.0477 \\ - 0.0147 & 1.6558 & 40.1707 & 0.6250 \\ - 0.4304 & - 0.0477 & 0.6250 & 39.4499 \end{matrix}]$	$[\begin{matrix} 53.3838 & - 2.9486 & - 6.8585 & 0.6519 \\ - 2.9486 & 41.8764 & 6.3582 & 1.3846 \\ - 6.8585 & 6.3582 & 39.5942 & 0.5691 \\ 0.6519 & 1.3846 & 0.5691 & 21.4551 \end{matrix}]$
n_R=2	$[\begin{matrix} 35.0483 & - 1.1796 & - 0.8304 & - 1.2195 \\ - 1.1796 & 34.9706 & 0.7818 & - 0.3830 \\ - 0.8304 & 0.7818 & 34.5182 & - 0.8047 \\ - 1.2195 & - 0.3830 & - 0.8047 & 34.9130 \end{matrix}]$	$[\begin{matrix} 36.7562 & - 1.2168 & 2.5448 & - 2.3932 \\ - 1.2168 & 35.7604 & - 4.5481 & 5.3259 \\ 2.5448 & - 4.5481 & 33.6259 & - 1.0237 \\ - 2.3932 & 5.3259 & - 1.0237 & 34.4099 \end{matrix}]$

表2

图1

图2

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图8

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